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A solution of glucose in water has a freezing point depression of $0.186\,\text{K}$. Given $K_f$ for water $= 1.86\,\text{K kg mol}^{-1}$, the molality of the solution is:
A$0.10\,\text{m}$
B$0.01\,\text{m}$
C$1.00\,\text{m}$
D$0.50\,\text{m}$
Answer & Solution
Correct answer: A. $0.10\,\text{m}$
$\Delta T_f = K_f m \Rightarrow m = \Delta T_f / K_f = 0.186 / 1.86 = 0.10\,\text{mol/kg}$. Glucose is a non-electrolyte so $i = 1$ and no correction is needed.
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