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If $\mathrm{NaCl}$ undergoes complete dissociation in water, the van't Hoff factor $i$ is:
A$1.5$
B$1.0$
C$2.0$
D$0.5$
Answer & Solution
Correct answer: C. $2.0$
$\mathrm{NaCl}\to \mathrm{Na^+ + Cl^-}$. Each formula unit gives two ions, so $i = 2$ for complete dissociation. The actually observed $i$ for $\mathrm{NaCl}$ in dilute solution is slightly less than $2$ due to interionic interactions.
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