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The elevation in boiling point of a solution is given by $\Delta T_b = K_b m$. The molal elevation constant $K_b$ for a solvent depends on:

AThe properties of the pure solvent (its molar mass, boiling point, enthalpy of vaporisation)
BThe molality of the solution
CThe nature of the solute only
DThe mole fraction of the solute
Answer & Solution
Correct answer: A. The properties of the pure solvent (its molar mass, boiling point, enthalpy of vaporisation)
$K_b = \dfrac{M_A R (T_b^\circ)^2}{\Delta H_v}$, where $M_A$, $T_b^\circ$ and $\Delta H_v$ are properties of the pure solvent. $K_b$ therefore depends only on the solvent, not on the identity or amount of solute, which is exactly why $\Delta T_b$ is a colligative property.
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