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The mole fraction of urea ($M = 60\,\text{g/mol}$) in an aqueous solution containing $6\,\text{g}$ of urea in $180\,\text{g}$ of water is approximately:
A$0.010$
B$0.005$
C$0.100$
D$0.050$
Answer & Solution
Correct answer: A. $0.010$
Moles of urea $= 6/60 = 0.10$. Moles of water $= 180/18 = 10.0$. Mole fraction of urea $= 0.10/(0.10 + 10.0) = 0.10/10.10 \approx 0.0099 \approx 0.010$.
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