Home › CBSE Class 11 › Physics › $\vec{F} = (6\hat{i} - 8\hat{j} + 10\hat{k})$ N …
$\vec{F} = (6\hat{i} - 8\hat{j} + 10\hat{k})$ N বল কোনো একটি ভরের ওপর ক্রিয়া করে 1 m s⁻¹ ত্বরণ সৃষ্টি করল। বস্তুটির ভর হল [CBSE PMT 1996]
A$10\sqrt{2}$ kg
B$2\sqrt{10}$ kg
C$10$ kg
D$20$ kg
Answer & Solution
Correct answer: A. $10\sqrt{2}$ kg
নিউটনের দ্বিতীয় সূত্র অনুযায়ী $F = ma$। তাই আগে বলের মান বের করি।
$$|\vec{F}| = \sqrt{6^2 + (-8)^2 + 10^2}$$
$$|\vec{F}| = \sqrt{36 + 64 + 100}$$
$$|\vec{F}| = \sqrt{200} = 10\sqrt{2}\,\mathrm{N}$$
ত্বরণ $1\,\mathrm{m\,s^{-2}}$ হলে,
$$m = \frac{F}{a}$$
$$m = \frac{10\sqrt{2}}{1} = 10\sqrt{2}\,\mathrm{kg}$$
অতএব সঠিক বিকল্প $A$।
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