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$\vec{P} + \vec{Q} = \vec{P} - \vec{Q}$ হলে [AIEEE 2002]
A$\vec{P}$ ও $\vec{Q}$ পরস্পর সমান্তরাল
B$\vec{P}$ ও $\vec{Q}$ পরস্পর লম্ব
C$\vec{P} = 0$
D$\vec{Q} = 0$
Answer & Solution
Correct answer: D. $\vec{Q} = 0$
সমীকরণটি থেকে দুই পাশে $\vec{P}$ বাদ দিলে পাই
$$\vec{Q}=-\vec{Q}$$
এখন দুই পাশে $\vec{Q}$ যোগ করলে পাই
$$2\vec{Q}=0$$
অতএব
$$\vec{Q}=0$$
এখন অপশনগুলো মিলিয়ে দেখি, এটি $(D)$-এর সঙ্গে মিলে।
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