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Plane-polarised light is incident on an analyser. If the angle between the polarisation direction of the light and the transmission axis of the analyser is $60^\circ$, the fraction of the incident intensity transmitted is:
A$1/4$
B$1/2$
C$3/4$
D$\sqrt{3}/2$
Answer & Solution
Correct answer: A. $1/4$
By Malus's law, $I = I_0\cos^2\theta = I_0\cos^2(60^\circ) = I_0 \times (1/2)^2 = I_0/4$.
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