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Unpolarised light of intensity $I_0$ is passed through a single ideal polariser. The intensity of the transmitted light is:
A$I_0$
B$I_0/2$
C$I_0\cos^2\theta$
D$I_0/4$
Answer & Solution
Correct answer: B. $I_0/2$
Unpolarised light contains all polarisation directions with equal probability. Averaging Malus's law over all input angles gives $\langle I \rangle = I_0 \langle\cos^2\theta\rangle = I_0/2$. Once polarised, a second polariser would then attenuate further by $\cos^2\theta$ relative to its axis.
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