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HomeUP Board Class 12 › Optics › Light of wavelength $500\,\text{nm}$ falls on a …

Light of wavelength $500\,\text{nm}$ falls on a single slit of width $0.1\,\text{mm}$. The angular width of the central maximum in the resulting diffraction pattern is:

A$5 \times 10^{-4}\,\text{rad}$
B$1 \times 10^{-2}\,\text{rad}$
C$1 \times 10^{-3}\,\text{rad}$
D$5 \times 10^{-3}\,\text{rad}$
Answer & Solution
Correct answer: B. $1 \times 10^{-2}\,\text{rad}$
The angular width of the central maximum in single-slit diffraction is $2\lambda/a$, where $a$ is the slit width. $2\lambda/a = 2 \times 500 \times 10^{-9} / (0.1 \times 10^{-3}) = 10^{-2}\,\text{rad}$.
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