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For a linear isotropic dielectric, polarisation P is related to field E by which relation?

AP = epsilon0 chi E
BP = chi divided by E
CP = E squared / chi
DP = epsilon0 / E
Answer & Solution
Correct answer: A. P = epsilon0 chi E
Polarisation is proportional to the field through the electric susceptibility: P equals epsilon-zero times chi times E.
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