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Two parabolas y² = 4ax and x² = 4ay cross at the origin and again. Area between them?
A16a²/3
B8a²/3
C4a²/3
Da²/3
Answer & Solution
Correct answer: A. 16a²/3
The curves meet at x = 0 and x = 4a, and the integral of (2√a·√x - x²/4a) from 0 to 4a equals 32a²/3 - 16a²/3 = 16a²/3.
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