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A 0.5 m rod carries 4 A across a 0.2 T field, at right angles. The force on it is

A0.2 N
B0.8 N
C1.6 N
D0.4 N
Answer & Solution
Correct answer: D. 0.4 N
F = I l B = 4 x 0.5 x 0.2 = 0.4 N when the rod is perpendicular to the field.
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