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An electron (9 x 10^-31 kg) at 3 x 10^7 m/s crosses a 6 x 10^-4 T field at right angles. Orbit radius?

A28 cm
B2.8 m
C2.8 cm
D0.28 cm
Answer & Solution
Correct answer: A. 28 cm
r = mv/(eB) = (9e-31 x 3e7)/(1.6e-19 x 6e-4), which is 0.28 m or 28 cm.
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