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The SI unit Henry (H) is equivalent to:
A$\text{Wb}\cdot\text{A}$
B$\text{V}\cdot\text{s}\cdot\text{A}^{-1}$
C$\text{T}\cdot\text{m}^2$
D$\text{V}\cdot\text{A}^{-1}$
Answer & Solution
Correct answer: B. $\text{V}\cdot\text{s}\cdot\text{A}^{-1}$
From $\varepsilon = -L \dfrac{dI}{dt}$, $L$ has units of $\text{V}/(\text{A/s}) = \text{V}\cdot\text{s}\cdot\text{A}^{-1}$. This is the same as $\text{Wb}/\text{A}$ since $1\,\text{Wb} = 1\,\text{V}\cdot\text{s}$.
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