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Applying parts twice, the antiderivative of x^2 e^x is

Ae^x (x^2 - 2) + C
Be^x (x^2 - 2x + 2) + C
Ce^x (x^2 + 2x + 2) + C
De^x (x^2 - 2x) + C
Answer & Solution
Correct answer: B. e^x (x^2 - 2x + 2) + C
Applying parts twice gives x^2 e^x - 2x e^x + 2e^x.
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