alleryStart learning →Changing the limits along with u = x^2 + 1, the integral of 2x(x^2 + 1)^3 over [0, 1] is
A15
B15/4
C1/4
D4
Answer & Solution
Correct answer: B. 15/4
With u = x^2 + 1 the limits become 1 and 2, and the integral of u^3 is (16 - 1)/4 = 15/4.
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