alleryStart learning →Using x = 2 tan(theta), the antiderivative of 1/(x^2 + 4) is
A(1/2) tan^-1(x/2) + C
Btan^-1(x/2) + C
C(1/2) ln(x^2 + 4) + C
D(1/4) tan^-1 x + C
Answer & Solution
Correct answer: A. (1/2) tan^-1(x/2) + C
With x = 2 tan(theta), dx = 2 sec^2(theta) dtheta, so the result is (1/2) tan^-1(x/2).
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