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From x = tan y, the slope of the inverse tangent curve at x is
A1/(1+x^2)
Bsec^2 x
C-1/(1+x^2)
D1/sqrt(1-x^2)
Answer & Solution
Correct answer: A. 1/(1+x^2)
Differentiating x = tan y gives dy/dx = 1/sec^2 y, which is 1/(1+x^2).
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