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Using differentials, what is the approximate value of the square root of 36.6?
A6.05
B6.005
C6.5
D6.1
Answer & Solution
Correct answer: A. 6.05
With f(x) = root x at 36, dy = 0.6/(2 x 6) = 0.05, so the value is about 6.05.
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