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What is the least value of f(x) = 2x - x^2 on the closed interval [0, 3]?

A-3
B0
C-1
D1
Answer & Solution
Correct answer: A. -3
Comparing f(0) = 0, the critical value f(1) = 1 and f(3) = -3 shows the least value is -3.
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