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Which point of the parabola y = x^2 is nearest to (0, 3)?

Ay-coordinate 3/2
By-coordinate 3
Cy-coordinate 5/2
Dy-coordinate 2
Answer & Solution
Correct answer: C. y-coordinate 5/2
Squared distance x^2 + (x^2 - 3)^2 has derivative 2x(2x^2 - 5), zero at x^2 = 5/2, so the nearest points have y = 5/2.
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