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The function f(x) = x^2 - 6x + 5 is strictly increasing for which values of x?

Ax > 5
Bx < 3
Cx > 3
Dx < 1
Answer & Solution
Correct answer: C. x > 3
f'(x) = 2x - 6 is positive exactly when x > 3, so the function rises there.
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