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For f(x) = x^3 - 3x, the derivative f'(x) is zero at
Ax = 3 only
Bx = sqrt(3)
Cx = 0 only
Dx = 1 and x = -1
Answer & Solution
Correct answer: D. x = 1 and x = -1
f' = 3x^2 - 3 = 3(x - 1)(x + 1), which vanishes at x = 1 and x = -1.
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