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Taking ln x as u and x dx as dv, the integral of x ln x is
A(x^2/2) ln x - x^2/2 + C
B(x^2/2) ln x - x^2/4 + C
Cx^2 ln x - x^2/4 + C
D(x^2/2) ln x + x^2/4 + C
Answer & Solution
Correct answer: B. (x^2/2) ln x - x^2/4 + C
With u = ln x, the result is (x^2/2) ln x minus the integral of x/2, which is x^2/4.
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