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Taking x as the first function, x e^x is integrated to
A(x + 1) e^x + C
Bx^2 e^x/2 + C
C(x - 1) e^x + C
Dx e^x + C
Answer & Solution
Correct answer: C. (x - 1) e^x + C
Taking u = x gives x e^x minus the integral of e^x, which is (x - 1) e^x.
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