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With a = 3 in the standard arctangent form, 1/(x^2 + 9) integrates to
A3 tan^-1(3x) + C
B(1/9) ln(x^2 + 9) + C
Ctan^-1(x/3) + C
D(1/3) tan^-1(x/3) + C
Answer & Solution
Correct answer: D. (1/3) tan^-1(x/3) + C
With a = 3 the standard form gives (1/3) tan^-1(x/3).
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