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For a > 0, which antiderivative corresponds to dx/sqrt(a^2 - x^2)?
Asin^-1(x/a) + C
B(1/a) sin^-1(x/a) + C
Ca sin^-1(x/a) + C
Dtan^-1(x/a) + C
Answer & Solution
Correct answer: A. sin^-1(x/a) + C
Putting x = a sin t gives dx = a cos t dt and sqrt(a^2 - x^2) = a cos t, so the integral is t.
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