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Letting t = ln x for (ln x)/x dx with x > 0 gives
A1/x^2 + C
B(ln x)^2/2 + C
Cln(ln x) + C
D(ln x)/x^2 + C
Answer & Solution
Correct answer: B. (ln x)^2/2 + C
Putting t = ln x gives dt = dx/x, so the integral is t^2/2.
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