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Substituting t = 2x + 1 integrates (2x + 1)^3 dx to
A(2x + 1)^4 + C
B3(2x + 1)^2 + C
C(2x + 1)^4/8 + C
D(2x + 1)^4/4 + C
Answer & Solution
Correct answer: C. (2x + 1)^4/8 + C
Putting t = 2x + 1 gives dx = dt/2, so the result is t^4/8.
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