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Rewriting tan x as sin x/cos x and integrating gives
A-ln|sec x| + C
Bln|sin x| + C
Csec^2 x + C
Dln|sec x| + C
Answer & Solution
Correct answer: D. ln|sec x| + C
Writing tan x = sin x/cos x and putting t = cos x gives -ln|cos x|, which equals ln|sec x|.
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