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Using the substitution t = x^2, the integral of 2x e^(x^2) dx becomes
Ax e^(x^2) + C
B2 e^(x^2) + C
Ce^x + C
De^(x^2) + C
Answer & Solution
Correct answer: D. e^(x^2) + C
With t = x^2, dt = 2x dx, so the integral reduces to the integral of e^t dt, which is e^t.
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