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Find F(x) if F'(x) = 3x^2 + 4x^3 and the constant is arbitrary.
Ax^3 + x^4 + C
B6x + 12x^2 + C
C3x^3 + 4x^4 + C
Dx^2 + x^3 + C
Answer & Solution
Correct answer: A. x^3 + x^4 + C
Each term is integrated by the power rule: 3x^2 gives x^3 and 4x^3 gives x^4.
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