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Rolle's theorem cannot be applied to f(x) = |x| on [-1, 1] because f fails to be differentiable at
Ax = 1
Bx = 2
Cx = 0
Dx = -1
Answer & Solution
Correct answer: C. x = 0
The graph of |x| has a sharp corner at x = 0, so no derivative exists there inside the open interval.
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