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For f(x) = x^3 on [0, 2], the value of c in the mean value theorem is
A1
B√2
C2/√3
D4/3
Answer & Solution
Correct answer: C. 2/√3
The average slope is (8 - 0)/2 = 4, and 3c^2 = 4 gives c = 2/√3 which lies in (0, 2).
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