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Which equation has roots twice those of x² - 3x + 2 = 0?
Ax² - 3x + 4 = 0
Bx² - 6x + 4 = 0
Cx² - 6x + 8 = 0
Dx² + 6x + 8 = 0
Answer & Solution
Correct answer: C. x² - 6x + 8 = 0
The original roots are 1 and 2, so the new roots 2 and 4 give sum 6 and product 8.
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