Where does y = ax² + bx + c cut the y-axis?
AAt y = a
BAt y = c
CAt y = c/a
DAt y = b
Answer & Solution
Correct answer: B. At y = c
Putting x = 0 gives y = c, the constant term.
Related questions
If a + b + c = 0, one root of ax² + bx + c = 0 isWhat is the range of x² + x + 1 over the real numbers?After which mathematician are the root-coefficient formulas named?Counting multiplicity, how many complex roots does a quadratic have?The discriminant of ax² + bx + c equals which expression of the roots α, β?In the form a(x - h)² + k, which point is the vertex?The word quadratic comes from a Latin word meaning what?If a = 0 and b is not zero in ax² + bx + c = 0, the equation is