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Find all x with sin x + cos x = √2, for integer n.
Ax = 2nπ - π/4
Bx = 2nπ + π/2
Cx = 2nπ + π/4
Dx = nπ + π/4
Answer & Solution
Correct answer: C. x = 2nπ + π/4
Since sin x + cos x = √2 sin(x + π/4), the value √2 needs x + π/4 = π/2 + 2nπ, so x = 2nπ + π/4.
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