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If sin x = sin α, the general solution for integer n is which one?
Ax = 2nπ ± α
Bx = nπ + (-1)ⁿα
Cx = nπ ± α
Dx = nπ + α
Answer & Solution
Correct answer: B. x = nπ + (-1)ⁿα
Equal sines occur for x = α or π minus α modulo 2π, and these two families combine into x = nπ + (-1)^n α.
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