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What is the general solution of the equation sin x = 0, with n an integer?

Ax = 2nπ
Bx = nπ
Cx = (2n+1)π
Dx = nπ/2
Answer & Solution
Correct answer: B. x = nπ
Sine vanishes at every integer multiple of π, including both 2nπ and (2n+1)π, so the full set is x = nπ.
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