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Which condition makes a1x + b1y + c1 = 0 and a2x + b2y + c2 = 0 perpendicular?
Aa1a2 + b1b2 = 0
Ba1b1 + a2b2 = 0
Ca1a2 - b1b2 = 0
Da1b2 - a2b1 = 0
Answer & Solution
Correct answer: A. a1a2 + b1b2 = 0
Slopes -a1/b1 and -a2/b2 multiply to -1 exactly when a1a2 + b1b2 = 0.
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