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The distance of (x1, y1) from Ax + By + C = 0 is
A|Ax1 + By1|/√(A² + B²)
B|Ax1 + By1 + C|/√(A² + B²)
C(Ax1 + By1 + C)/√(A² - B²)
D|Ax1 + By1 + C|/(A + B)
Answer & Solution
Correct answer: B. |Ax1 + By1 + C|/√(A² + B²)
The perpendicular distance divides the absolute value of the line expression by the root of the sum of squared coefficients.
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