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The cubic x^3 - 6x^2 + 11x - 6 = 0 has roots 1, 2 and 3. What is the sum of the squares of its roots?
A12
B14
C16
D36
Answer & Solution
Correct answer: B. 14
The square of the sum is 36 and twice the pair-product sum is 22, so the sum of squares is 36 - 22 = 14.
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