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The zeroes of the polynomial $x^2 - 3x - 4$ are:

A2 and −2
B4 and −1
C3 and 4
D−4 and 1
Answer & Solution
Correct answer: B. 4 and −1
x² − 3x − 4 = (x − 4)(x + 1), so the zeroes are 4 and −1.
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