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For a quadratic $ax^2 + bx + c$, the sum of its zeroes is:
A$\dfrac{b}{a}$
B$-\dfrac{c}{a}$
C$-\dfrac{b}{a}$
D$\dfrac{c}{a}$
Answer & Solution
Correct answer: C. $-\dfrac{b}{a}$
For ax² + bx + c, sum of zeroes = −b/a.
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