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A coil of self-inductance 0.2 H has its current changing at 5 A/s. What is the self-induced emf?
A0.04 V
B1 V
C25 V
D10 V
Answer & Solution
Correct answer: B. 1 V
Magnitude of emf = L x dI/dt = 0.2 x 5 = 1 V.
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