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Which is the hyperbolic analogue of de Moivre's formula?
A(cosh x + sinh x)^n = n cosh x
Bcosh^n x + sinh^n x = cosh nx
C(cosh x + sinh x)^n = cosh nx + sinh nx
D(cosh x − sinh x)^n = cosh nx + sinh nx
Answer & Solution
Correct answer: C. (cosh x + sinh x)^n = cosh nx + sinh nx
Because cosh x + sinh x = e^x, its n-th power is e^(nx) = cosh nx + sinh nx.
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