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On which interval is sin x one-to-one?
A[-π/2, π/2]
B[0, 2π]
C[-π, π]
D[0, π]
Answer & Solution
Correct answer: A. [-π/2, π/2]
Sine rises steadily from -1 to 1 over [-π/2, π/2], so it takes no value twice there.
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