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If y = (2x + 8)³, then x expressed in terms of y is
A(y^3 + 8)/2
B(y^3 - 8)/2
C(y^(1/3) - 8)/2
D2y^(1/3) - 8
Answer & Solution
Correct answer: C. (y^(1/3) - 8)/2
Taking the cube root gives 2x + 8 = y^(1/3), so x = (y^(1/3) - 8)/2.
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