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Which plane is perpendicular to the plane 2x + 3y - z = 1?
A2x + 3y - z = 9
Bx + y + z = 4
C2x - 3y + z = 4
Dx - y - z = 4
Answer & Solution
Correct answer: D. x - y - z = 4
The normals (2,3,-1) and (1,-1,-1) have dot product 2 - 3 + 1 = 0, so the planes meet at right angles.
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