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A plane cuts the axes at x = 2, y = 3 and z = 6. Which is its equation?
A3x + 2y + z = 6
Bx + y + z = 11
C6x + 3y + 2z = 6
D2x + 3y + 6z = 1
Answer & Solution
Correct answer: A. 3x + 2y + z = 6
In intercept form x/2 + y/3 + z/6 = 1; multiplying by 6 gives 3x + 2y + z = 6.
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